Create s3_list_bucket_contents_fromfile.py

rename + add a comment
This commit is contained in:
Chris Gates
2017-06-12 21:32:12 -04:00
committed by GitHub
parent 46fd3b148f
commit 1755a6e809

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@@ -14,6 +14,7 @@ from s3.s3 import *
AWS_ACCESS_KEY_ID = ''
AWS_SECRET_ACCESS_KEY =''
#open a list of possible buckets and attempt to list the contents
f = open('test.txt', 'r')
for line in f:
line = line.strip()