list s3 buckets for an account
This commit is contained in:
21
s3/s3.py
21
s3/s3.py
@@ -102,3 +102,24 @@ def get_s3object_acl(access_key, secret_key, bucket, myfile):
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print('%s : doesnt have s3 access' % AWS_ACCESS_KEY_ID)
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else:
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print "Unexpected error: %s" % e
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def get_s3objects_foraccount(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
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client = boto3.resource(
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's3',
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aws_access_key_id=AWS_ACCESS_KEY_ID,
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aws_secret_access_key=AWS_SECRET_ACCESS_KEY,
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region_name='us-east-1'
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)
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try:
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print('#### Trying to list s3 bucketsfor {} ####\n '.format(AWS_ACCESS_KEY_ID))
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for bucket in client.buckets.all():
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print(bucket.name)
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except botocore.exceptions.ClientError as e:
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if e.response['Error']['Code'] == 'InvalidClientTokenId':
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sys.exit("The AWS KEY IS INVALID. Exiting")
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elif e.response['Error']['Code'] == 'NotSignedUp':
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print('%s : doesnt have s3 access' % AWS_ACCESS_KEY_ID)
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else:
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print "Unexpected error: %s" % e
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23
s3_list_buckets_for_acct.py
Normal file
23
s3_list_buckets_for_acct.py
Normal file
@@ -0,0 +1,23 @@
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import boto3
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import botocore
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import json
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import urllib
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import logging
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import sys,os
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import pprint
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pp = pprint.PrettyPrinter(indent=5, width=80)
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from s3.s3 import *
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#insert AWS key, will figure out how to pull this in from a single file for all scripts
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AWS_ACCESS_KEY_ID = ''
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AWS_SECRET_ACCESS_KEY =''
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#client = boto3.resource('s3')
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#for bucket in client.buckets.all():
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# print(bucket.name)
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get_s3objects_foraccount(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY)
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