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believe the last of the print issues should be fixed

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This commit is contained in:
cktricky
2018-04-06 11:11:50 -10:00
parent f9e8d453ad
commit 3ae87d030a
5 changed files with 28 additions and 29 deletions
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9
libs/ec2.py
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@@ -49,7 +49,7 @@ def review_encrypted_volumes(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
if e.response['Error']['Code'] == 'UnauthorizedOperation': if e.response['Error']['Code'] == 'UnauthorizedOperation':
print('{} : (UnauthorizedOperation) when calling the DescribeVolumes -- sure you have ec2 permissions?' .format(AWS_ACCESS_KEY_ID)) print('{} : (UnauthorizedOperation) when calling the DescribeVolumes -- sure you have ec2 permissions?' .format(AWS_ACCESS_KEY_ID))
else: else:
print e print(e)
except KeyboardInterrupt: except KeyboardInterrupt:
print("CTRL-C received, exiting...") print("CTRL-C received, exiting...")
@@ -70,7 +70,7 @@ def get_instance_details(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
pp.pprint(i) pp.pprint(i)
except botocore.exceptions.ClientError as e: except botocore.exceptions.ClientError as e:
print e print(e)
except KeyboardInterrupt: except KeyboardInterrupt:
print("CTRL-C received, exiting...") print("CTRL-C received, exiting...")
@@ -93,7 +93,7 @@ def get_instance_volume_details(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
pp.pprint(volumes) pp.pprint(volumes)
except botocore.exceptions.ClientError as e: except botocore.exceptions.ClientError as e:
print e print(e)
except KeyboardInterrupt: except KeyboardInterrupt:
print("CTRL-C received, exiting...") print("CTRL-C received, exiting...")
@@ -117,7 +117,6 @@ def get_instance_volume_details2(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
print("\n") print("\n")
except botocore.exceptions.ClientError as e: except botocore.exceptions.ClientError as e:
print e print(e)
except KeyboardInterrupt: except KeyboardInterrupt:
print("CTRL-C received, exiting...") print("CTRL-C received, exiting...")

2
libs/iam.py
View File

@@ -38,7 +38,7 @@ def check_root_account(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
print('User {} likely has console access and the password can be reset :-)' .format(user['UserName'])) print('User {} likely has console access and the password can be reset :-)' .format(user['UserName']))
print("Checking for MFA on account") print("Checking for MFA on account")
mfa = client.list_mfa_devices(UserName=user['UserName']) mfa = client.list_mfa_devices(UserName=user['UserName'])
print mfa['MFADevices'] print(mfa['MFADevices'])
except botocore.exceptions.ClientError as e: except botocore.exceptions.ClientError as e:
if e.response['Error']['Code'] == 'NoSuchEntity': if e.response['Error']['Code'] == 'NoSuchEntity':

2
libs/opsworks.py
View File

@@ -22,7 +22,7 @@ def describe_stacks(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
) )
response = client.describe_stacks() response = client.describe_stacks()
#debug #debug
print response print(response)
if response.get('Stacks') is None: if response.get('Stacks') is None:
print("{} likely does not have Lambda permissions\n" .format(AWS_ACCESS_KEY_ID)) print("{} likely does not have Lambda permissions\n" .format(AWS_ACCESS_KEY_ID))
elif len(response['Stacks']) <= 0: elif len(response['Stacks']) <= 0:

2
libs/rds.py
View File

@@ -25,6 +25,6 @@ def describe_db_instances(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY):
pp.pprint(i) pp.pprint(i)
except botocore.exceptions.ClientError as e: except botocore.exceptions.ClientError as e:
print e print(e)
except KeyboardInterrupt: except KeyboardInterrupt:
print("CTRL-C received, exiting...") print("CTRL-C received, exiting...")

2
logging_list_monitoring_configuration.py
View File

@@ -55,6 +55,6 @@ for region in regions:
# pp.pprint(resourcetype['resourceTypes'][0]) # pp.pprint(resourcetype['resourceTypes'][0])
ruleresponse = describe_configuration_recorders(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY, region) ruleresponse = describe_configuration_recorders(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY, region)
print ruleresponse print(ruleresponse)
print_section_header_and_footer("END OF CONFIG SERVICE REVIEW", True) print_section_header_and_footer("END OF CONFIG SERVICE REVIEW", True)